Question

If tanx= 1/2 and tany=1/3
What is tan(x+y)?

Answer 1

\[\tan(x+y) = \dfrac{\tan x + \tan y }{1 - \tan x \tan y}\]

Answer 2

\[\tan(x+y)=\frac{ \tan1/2 + \tan1/3 }{ 1- \tan1/2 \tan1/3 }\]

Answer 3

Is that right?

Answer 4

You're given that \(\tan x = 1/2\), \(\tan y = 1/3\) and not \(x = 1/2\), \(y = 1/3 \).

So you will say that\[\tan(x + y) = \dfrac{1/2 + 1/3}{1 - (1/2)(1/3)}\]Do you understand?

Answer 5

so you remove the tan?

Answer 6

Is it cancellatin?

Answer 7

\[\tan(x + y) = \dfrac{\tan x + \tan y }{1 - \tan x \tan y}\]Sinice you are given \(\tan x = 1/2\) and \(\tan y = 1/3\), you will replace \(\tan x\) with \(1/2\) and \(\tan y \) with \(1/3\) in the formula.

Answer 8

oh i see

Answer 9

u just replace it with the value already given in the question