Question

1. Calculate the energy change (q) of the surroundings (water). We can assume that the specific heat capacity of water is 4.18 J/ (g · °C), and the density of water is 1.00 g/mL. (4 points)

Answer 1

How much water did you use? What was the temperature change in the water?

Answer 2

Metal Name copper
Mass of Metal 29.884
Volume of water 36.1mL
Initial temp. in calorimeter 35.3C
Initial temp. in beaker 100.7C
Final temp. of mixture 33.1C

Answer 3

Use the formula \(q=m*C_P*(T_f-T_i)\)

m=mass
\(C_p\)=specific heat capacity
\(T_f\)=final temp
\(T_i\)=initial temp

This only needs to include information about the water and not the metal.

Answer 4

I don't understand...

Answer 5

what dont you understand?

Answer 6

what i am calculating

Answer 7

the heat (q) absorbed by the water.