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Mathematics 14 Online
OpenStudy (wyattp17):

Find the measure of angle P in the triangle below.

OpenStudy (wyattp17):

|dw:1406996503674:dw|

OpenStudy (science0229):

Do you know the Law of Cosine?

OpenStudy (wyattp17):

sorta @science0229

OpenStudy (science0229):

What is it?

OpenStudy (wyattp17):

Law of Cosines is c^2= a^2 + b^2 - Ab cos ( c )

OpenStudy (wyattp17):

@science0229

OpenStudy (science0229):

close. It's\[c^2=a^2+b^2-2ab \cos \theta\] where theta is the angle between a and b

OpenStudy (wyattp17):

theres not angle given

OpenStudy (science0229):

No. But all three sides are given, right?

OpenStudy (science0229):

Your goal is to find that angle.

OpenStudy (wyattp17):

explain how to get it

OpenStudy (science0229):

Since you have to find angle P, the 2 sides that has P between are RP and QP, right?

OpenStudy (wyattp17):

yea

OpenStudy (science0229):

so, a=RP=60 and b=QP=36 Automatically, c=RQ=48

OpenStudy (wyattp17):

i understand that 60 is an angle right

OpenStudy (science0229):

No. All of the numerical values right now are the sides of the triangle.

OpenStudy (wyattp17):

ok

OpenStudy (science0229):

Do understand so far?

OpenStudy (wyattp17):

oh yea i do i get it

OpenStudy (science0229):

You should get up to here:\[48^2=60^2+36^2-2(60)(36)\cos \theta\]

OpenStudy (wyattp17):

ok

OpenStudy (wyattp17):

so u plug it in ?

OpenStudy (science0229):

Solve for cos theta to get \[\cos \theta=\frac{ 60^2+36^2-48^2 }{ 2(60)(36) }=\frac{ 3 }{ 5 }\]

OpenStudy (wyattp17):

ok let me try doing this on my calculator real quick

OpenStudy (wyattp17):

what do i do with 3/5

OpenStudy (science0229):

have you learned inverse trig function, yet? Something like \[\cos^{-1} \] or arccos

OpenStudy (wyattp17):

not that i remember

OpenStudy (science0229):

Ok. It'll be brief

OpenStudy (wyattp17):

ok

OpenStudy (wyattp17):

thx for explaining this :)

OpenStudy (science0229):

Inverse Trig Function is literally the inverse of trig function. In other words, it "reverses" the trig function.

OpenStudy (science0229):

Mathematically, it would be this:\[y=\sin(x)\] To "reverse" this...\[x=\sin(y)\] Solve for y. This is when the inverse trig function come into play. Mathematicians defined the inverse trig function as this:\[y=\sin^{-1} (x)\]

OpenStudy (wyattp17):

so then what

OpenStudy (science0229):

For our original problem, we came to the conclusion that \[\cos \theta=\frac{ 3 }{ 5 }\]

OpenStudy (science0229):

This means that for some kind of value theta, cos(theta) is 3/5. To find this theta, we use the definition of inverse trig function:\[\theta=\cos^{-1} \frac{ 3 }{ 5 }\]

OpenStudy (science0229):

Are you lost?

OpenStudy (wyattp17):

kinda

OpenStudy (science0229):

Yeah. I'm not a very good explainer... What grade are you?

OpenStudy (wyattp17):

sophmore

OpenStudy (science0229):

Then I'm thinking that you'll learn this soon in your math class.

OpenStudy (wyattp17):

whats the answer at least

OpenStudy (science0229):

do you have a calculator?

OpenStudy (wyattp17):

yea

OpenStudy (science0229):

what kind?

OpenStudy (wyattp17):

Ti-84 plus

OpenStudy (science0229):

Do you have to find this angle in degrees or radians?

OpenStudy (wyattp17):

radians i think

OpenStudy (science0229):

Then put your calculator in radian mode. You know how to do it, right?

OpenStudy (wyattp17):

um I'm trying right now

OpenStudy (science0229):

http://www.youtube.com/watch?v=9Dg56o6G0MI

OpenStudy (wyattp17):

thx

OpenStudy (wyattp17):

ok its in radians

OpenStudy (wyattp17):

@science0229

OpenStudy (science0229):

Because 3/5=0.6, type in 0.6

OpenStudy (science0229):

Now, press the 2nd button and the sin button

OpenStudy (wyattp17):

sin of 0.6?

OpenStudy (science0229):

Wait. Do 2nd button and the COS button my mistake

OpenStudy (science0229):

You must press 2nd first

OpenStudy (science0229):

what did you get?

OpenStudy (wyattp17):

.92

OpenStudy (science0229):

That's your answer, then.

OpenStudy (science0229):

.92 radians

OpenStudy (wyattp17):

thx for being patient with me and teaching me

OpenStudy (science0229):

Welcome :)

OpenStudy (wyattp17):

byeeee

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