Find the measure of angle P in the triangle below.
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OpenStudy (wyattp17):
|dw:1406996503674:dw|
OpenStudy (science0229):
Do you know the Law of Cosine?
OpenStudy (wyattp17):
sorta @science0229
OpenStudy (science0229):
What is it?
OpenStudy (wyattp17):
Law of Cosines is c^2= a^2 + b^2 - Ab cos ( c )
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OpenStudy (wyattp17):
@science0229
OpenStudy (science0229):
close.
It's\[c^2=a^2+b^2-2ab \cos \theta\] where theta is the angle between a and b
OpenStudy (wyattp17):
theres not angle given
OpenStudy (science0229):
No. But all three sides are given, right?
OpenStudy (science0229):
Your goal is to find that angle.
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OpenStudy (wyattp17):
explain how to get it
OpenStudy (science0229):
Since you have to find angle P, the 2 sides that has P between are RP and QP, right?
OpenStudy (wyattp17):
yea
OpenStudy (science0229):
so, a=RP=60 and b=QP=36
Automatically, c=RQ=48
OpenStudy (wyattp17):
i understand that 60 is an angle right
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OpenStudy (science0229):
No. All of the numerical values right now are the sides of the triangle.
OpenStudy (wyattp17):
ok
OpenStudy (science0229):
Do understand so far?
OpenStudy (wyattp17):
oh yea i do i get it
OpenStudy (science0229):
You should get up to here:\[48^2=60^2+36^2-2(60)(36)\cos \theta\]
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OpenStudy (wyattp17):
ok
OpenStudy (wyattp17):
so u plug it in ?
OpenStudy (science0229):
Solve for cos theta to get \[\cos \theta=\frac{ 60^2+36^2-48^2 }{ 2(60)(36) }=\frac{ 3 }{ 5 }\]
OpenStudy (wyattp17):
ok let me try doing this on my calculator real quick
OpenStudy (wyattp17):
what do i do with 3/5
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OpenStudy (science0229):
have you learned inverse trig function, yet?
Something like \[\cos^{-1} \] or arccos
OpenStudy (wyattp17):
not that i remember
OpenStudy (science0229):
Ok. It'll be brief
OpenStudy (wyattp17):
ok
OpenStudy (wyattp17):
thx for explaining this :)
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OpenStudy (science0229):
Inverse Trig Function is literally the inverse of trig function.
In other words, it "reverses" the trig function.
OpenStudy (science0229):
Mathematically, it would be this:\[y=\sin(x)\]
To "reverse" this...\[x=\sin(y)\]
Solve for y. This is when the inverse trig function come into play.
Mathematicians defined the inverse trig function as this:\[y=\sin^{-1} (x)\]
OpenStudy (wyattp17):
so then what
OpenStudy (science0229):
For our original problem, we came to the conclusion that \[\cos \theta=\frac{ 3 }{ 5 }\]
OpenStudy (science0229):
This means that for some kind of value theta, cos(theta) is 3/5.
To find this theta, we use the definition of inverse trig function:\[\theta=\cos^{-1} \frac{ 3 }{ 5 }\]
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OpenStudy (science0229):
Are you lost?
OpenStudy (wyattp17):
kinda
OpenStudy (science0229):
Yeah. I'm not a very good explainer...
What grade are you?
OpenStudy (wyattp17):
sophmore
OpenStudy (science0229):
Then I'm thinking that you'll learn this soon in your math class.
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OpenStudy (wyattp17):
whats the answer at least
OpenStudy (science0229):
do you have a calculator?
OpenStudy (wyattp17):
yea
OpenStudy (science0229):
what kind?
OpenStudy (wyattp17):
Ti-84 plus
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OpenStudy (science0229):
Do you have to find this angle in degrees or radians?
OpenStudy (wyattp17):
radians i think
OpenStudy (science0229):
Then put your calculator in radian mode.
You know how to do it, right?