How do I factor x^2 + 12x + 0 using the guess and check method?
take x common and that's it, i guess..
x(x+12)=0 x=0 and x=-12
I don't understand either answer.
I know how to factor using guess and check method, but I don't understand how to do it to this one. I know that I have to find a factor pair of the second term that would add up to the third term, but I can' do that here. So how do I factor this using guess and check method? x^2 + 12x + 0
@ParthKohli ?
@paki ?
what about quadratic formula... ?
What is the quadratic formula? Well anyway I have to use the guess and check method.
Will someone please help?
You have had two perfectly good answers. If you can factor, as you say, just factor x out of the original equation. Lose the zero. It is is just window dressing.
I don't understand how to do that.
How do I factor x?
I only know how to factor constants.
Okay \( x^2 = x \cdot x\) so your original expression is \( x \cdot x + 12x\)
The only constant is 0. It is nothing. So just drop it.
Ok. I understand that, but how would I use the guess and check method for this? I'm supposed to get an answer that looks like this: (x + a)(x + b)
Factor the x out: \[ x\cdot x + 12x = x(x+12) \] If it makes you feel better, you can rewrite x as x + 0, but it is kind of pointless. \[ x\cdot x + 12x = x(x+12) = (x+0)(x+12)\]
Oh, now I understand.
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S'k
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