Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (yanasidlinskiy):

Factor help!!!

OpenStudy (yanasidlinskiy):

\[x^3-5x^2+3x-15\]

ganeshie8 (ganeshie8):

factor the GCF from first two terms factor the GCF from last two terms

ganeshie8 (ganeshie8):

\[\large x^3-5x^2+3x-15\] \[\large (x^3-5x^2)+(3x-15)\]

OpenStudy (yanasidlinskiy):

Ok. Lemme see what I can get. I'm not used to x^3 only. But I'll give it a try.

ganeshie8 (ganeshie8):

okie

OpenStudy (yanasidlinskiy):

Ok. I have nooo idea. I'mm stuck.

ganeshie8 (ganeshie8):

heard of the term GCF before ?

OpenStudy (yanasidlinskiy):

Yes. I have.

ganeshie8 (ganeshie8):

well you have heard of it i knw :) what i mean is do you know how to find GCF of two terms ?

ganeshie8 (ganeshie8):

\[\large \color{Red}{ (x^3-5x^2)}+(3x-15)\]

ganeshie8 (ganeshie8):

can you find GCF of those two first terms ?

OpenStudy (yanasidlinskiy):

Not really. It's just that these types of problems that I'm confused. Like the other ones with all the #'s and variables, I'm okay. Hang on.

OpenStudy (yanasidlinskiy):

Wait wait wait!! I think I have it. Don't write the answer.

OpenStudy (yanasidlinskiy):

Just Kidding. I dunno.

ganeshie8 (ganeshie8):

\[\large \color{Red}{ (x^3-5x^2)}+(3x-15)\] \[\large \color{Red}{x^2 (x-5)}+3(x-5)\] \[\large (x-5)(x^2+3)\]

ganeshie8 (ganeshie8):

Notice that GCF of \(\large x^3\) and \(\large -5x^3\) is \(\large x^2\), and the GCF of \(\large 3x\) and \(\large -15\) is \(\large 3\)

OpenStudy (yanasidlinskiy):

Ok. I see what you did. Makes sense. Would the final answer be: (x-5)(x^2+3)?

ganeshie8 (ganeshie8):

Yep !

OpenStudy (yanasidlinskiy):

Haha!!:D Ok. I have a similar one But I'll try to figure it out and tell you what I got.

OpenStudy (yanasidlinskiy):

Imma make a new postXD. And thanx sooooooooooooo much:D For your help!!!!

ganeshie8 (ganeshie8):

np :) good luck !

OpenStudy (yanasidlinskiy):

Thanx.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!