Factor help!!!
\[x^3-5x^2+3x-15\]
factor the GCF from first two terms factor the GCF from last two terms
\[\large x^3-5x^2+3x-15\] \[\large (x^3-5x^2)+(3x-15)\]
Ok. Lemme see what I can get. I'm not used to x^3 only. But I'll give it a try.
okie
Ok. I have nooo idea. I'mm stuck.
heard of the term GCF before ?
Yes. I have.
well you have heard of it i knw :) what i mean is do you know how to find GCF of two terms ?
\[\large \color{Red}{ (x^3-5x^2)}+(3x-15)\]
can you find GCF of those two first terms ?
Not really. It's just that these types of problems that I'm confused. Like the other ones with all the #'s and variables, I'm okay. Hang on.
Wait wait wait!! I think I have it. Don't write the answer.
Just Kidding. I dunno.
\[\large \color{Red}{ (x^3-5x^2)}+(3x-15)\] \[\large \color{Red}{x^2 (x-5)}+3(x-5)\] \[\large (x-5)(x^2+3)\]
Notice that GCF of \(\large x^3\) and \(\large -5x^3\) is \(\large x^2\), and the GCF of \(\large 3x\) and \(\large -15\) is \(\large 3\)
Ok. I see what you did. Makes sense. Would the final answer be: (x-5)(x^2+3)?
Yep !
Haha!!:D Ok. I have a similar one But I'll try to figure it out and tell you what I got.
Imma make a new postXD. And thanx sooooooooooooo much:D For your help!!!!
np :) good luck !
Thanx.
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