Question

Divide x to the 1 half power divided by x to the 2 sevenths power.

Answer 1

well dividing, the index law is subtract the powers...

so its

\[x^{\frac{1}{2} - \frac{2}{7}} = x^?\]

find the value of ?

Answer 2

So it would be x^3/14

Answer 3

\(\Large {
\cfrac{1}{\frac{1}{a^{\color{red} n}}}\implies a^{{\color{red} n}}
\\ \quad \\ \quad \\

\cfrac{x^{\frac{1}{2}}}{x^{\frac{2}{7}}}\implies \cfrac{x^{\frac{1}{2}}}{1}\cdot \cfrac{1}{x^{\frac{2}{7}}}\implies x^{\frac{1}{2}}\cdot x^{-\frac{2}{7}}\implies ?
}\)

Answer 4

I got it right on my exam. Thanks!

Answer 5

hmmm I even got the wrong.... set... anyhow \(\Large \bf {
\cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}}\implies a^{-\frac{{\color{blue} n}}{{\color{red} m}}}
\\ \quad \\ \quad \\

\cfrac{x^{\frac{1}{2}}}{x^{\frac{2}{7}}}\implies \cfrac{x^{\frac{1}{2}}}{1}\cdot \cfrac{1}{x^{\frac{2}{7}}}\implies x^{\frac{1}{2}}\cdot x^{-\frac{2}{7}}\implies ? }\)

Answer 6

My answer was x^3/14

Answer 7

yeap