Prove tan(y-z)+tan(z-x)+tan(x-y)=tan(y-z)tan(z-x)tan(x-y)

Question

crashonce · Answer

@ikram002p @ganeshie8 @bahrom7893

crashonce · Answer

@zepdrix  please help guys

crashonce · Answer

@ikram002p any ideas?

ikram002p · Answer

im trying :)
ill see if anything come out

crashonce · Answer

thanks

crashonce · Answer

@mayankdevnani any ideas

mayankdevnani · Answer

@CrashOnce  this is a conditional identity :-
$$\large \bf \tan A+tanB+tanC=tanAtanBtanC$$
where,
$$\large \bf A=y-z,B=z-x ~and~ C=x-y$$
REMEMBER :-
$$\large \bf A+B+B=180^o=\pi$$

crashonce · Answer

yes @mayankdevnani that is what im trying to prove

xapproachesinfinity · Answer

use tang identity of sum? for all the tangents there is!
and see what you get, manipulate that and see

mayankdevnani · Answer

*REMEMBER :-$$\large \bf A+B+C=180^o=\pi$$

crashonce · Answer

i dont know the generating product formula for tangent

crashonce · Answer

@mayankdevnani im assuming a+B+C=180 but it dosnt say

mayankdevnani · Answer

this is a conditional identity,remember if it is not given about angles we assume our condition that they form 180 degrees

crashonce · Answer

yes i am trying to prove the identity, how do i do it

mayankdevnani · Answer

https://www.youtube.com/watch?v=XE8rQ8XW69A https://in.answers.yahoo.com/question/index?qid=20080520205215AARB7M3 @CrashOnce go through them

xapproachesinfinity · Answer

tan(a-b)=( tana -tanb)/(1+tanatanb) i think this will work

mayankdevnani · Answer

hope you understand.  @CrashOnce

crashonce · Answer

thanks@mayank

mayankdevnani · Answer

welcome :)