will somebody help me with my homework? A body slides down in a frictionless plane during the third second after starting from rest it travels 19.4 meters. What is the angle of the plane? Thanks in advance
x= 0.5 g t^2
|dw:1407057873069:dw|
oh i forgot to put sin theta in my equation.
Since it took 3 seconds to travel 19.4 meters, its final velocity is 19.4/3 Its initial velocity is 0, of course, since it was at rest, first.
@Careless
Using the work-energy theorem...\[Work=(Force)(Distance)=\Delta (Kinetic Energy)=\frac{ 1 }{ 2 }m {v _{f}}^2-\frac{ 1 }{ 2 }m {v _{i}}^2\]
vf is the final velocity, which is 19.4/3 vi is the initial velocity, which is 0 Distance is 19.4
Force is as following|dw:1407058991396:dw|
I'm guessing that you're using 9.8 for the gravitational acceleration (of Earth)
since we're on the inclined plane, the force would be \[9.8m \sin \theta\]
Substitute all of that in the work-energy theorem
\[9.8m \sin \theta*19.4=\frac{ 1 }{ 2 }m (\frac{ 19.4 }{ 3 })^2\]
Solve for sin to get\[\sin \theta=\frac{ 97 }{ 882 }\]
You can solve for theta on your own.
If the gravitational acceleration is 'g', then the final equation would turn out as\[\sin \theta=\frac{ 97 }{ 90g }\]
This turned out ugly...
@Catch.me Did I do something wrong? When the answer comes out like this, I always have a feeling that I made a mistake somewhere
I didn't follow ,but the main idea is right (don't mind about small errors you just give the keys to answer it :D)
I guess so :)
thank you :)
an arrow is shot vertically upward with a speed of 288 fps and 3 seconds later another arrow is shot up with a speed of 244 fps. will they meet? if so, where?
please answer this another question :)
Hey show your work and why can't solve it?
after i have finish my homework i will show my solution ok? I'm sorry because i am very busy right now. We have midterm this week. so stay still. until i show my solution. Thank you for understanding.
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