Question

the equilibrium mixture given beow contain 5 moles of CO and 2 moles of H2O the volume of container is 1 litre
Co+H2O-------->Co2+H2
at equilibrium 0.5 moles of H2O are Present the value of Kc for the reaction is=?

Answer 1

First check/balance equation:
CO + H2O = CO2 + H2
Volume of container = 1 L
so all quantities in moles are equivalent to concentration in mol/L
Use ICE table
CO H2O CO2 H2
Initial 5 2 0 0
change -x -x x x
Final 5-x 2-x x x
All reactants and products are in gas form:
At equilibrium, 0.5 moles of H2O left, so 0.5=2-x, or x=1.5
\(Kc=\large \frac{[CO2]^1[H2]^1}{[CO]^1[H2p]^1}\)
\(\large =\frac{x^2}{(5-x)(2-x)}\)
Substitute x=1.5 to find Kc

Answer 2

thanx

Answer 3

You're welcome! :)