Question

a weight of 4.00N is hung from the string and the frequency of oscillation is adjusted until a stationary wave is formed on the string. the separation of the antinodes on the string is 17.8cm for a frequency of 125 Hz. The speed v of waves on a string is given by the expression v = sqrt(T/m) where T is the tension in the string and m is its mass per unit length. Determine the mass per unit length of the string

Answer 1

https://thol.sunway.edu.my/examdbase/alv/phy/p2/phy_p2_j08.pdf

Answer 2

It's question 5 on the above link

Answer 3

velocity=frequency.wavelength..the seperations between the antinodes is nothing but the wavelength so u can get the mass per unit length by using the formula sqrt T/M

Answer 4

Thanks!