Question

always have issues with fractions have problems with this equation. solve by substitution. 3x-2y=3

x-1/3y=8

Answer 1

Solve one of the equations for Y.

Answer 2

-2y=-3+2 divide by 2 y= 3/2+1

Answer 3

Are the two equations you put in the original question the two in the system of equations?

Answer 4

yes

Answer 5

Because if so, the easiest way to do it is actually to solve for x in the second equation, then plug in what x is equal to into the first equation. You then solve for y like normal, at which point you should have the final value for y. Plug the number for y into either equation, and solve for x. You now have the values for x and y.

Answer 6

If you need to use substitution, the easiest way to do it is to find an x or y value that has no coefficient, so things don't get complicated.

Answer 7

Or technically, the coefficient is 1, since every number has some coefficient.

Answer 8

if i have x-1/3y=8 = -1/3y =8-x

Answer 9

and then substitute that into the first eqation

Answer 10

how is the coefficient technically 1?

Answer 11

\[3x-2y=3\ ............(1)\]
\[x-\frac{1}{3}y=8\ ............(2)\]
We can find a value for x in terms of y from equation (2) by adding (1/3)y to both sides, giving:
\[x=\frac{1}{3}y+8\ ........(3)\]
Now we can substitute the value of x in equation (3) into equation (1) giving:
\[3(\frac{1}{3}y+8)-2y=3\ .......(4)\]
Removing the brackets in equation (4) gives:
\[y+24-2y=3\ ......(5)\]
Now you should be able to solve equation (5) to find the value of y.

Answer 12

thank you

Answer 13

You're welcome :)