A given amount of water cools from 68.4C to 56.7C. During this cooling process, 12.4 kcal are released into the surrounding area. What is the water’s mass? will medal

Question

aaronq · Answer

$q=m*C_p*\Delta T$

Solve for m

anonymous · Answer

m is mass, delta t is change in temperature, what is q and Cp?

aaronq · Answer

q is the heat (thermal energy) and $C_P$ is the specific heat capacity

anonymous · Answer

12.4 = m * 4.179 * 11.7
m = .2536
does this look right?

anonymous · Answer

.2536 grams or kilograms?

aaronq · Answer

what are the units on the heat capacity?

aaronq · Answer

they were probably "$J/g ^oC$"

so before you use 12.4 kcal, you need to convert them to joules.

1 kcal = 4184 J

anonymous · Answer

51,881.6 = m * 4.179 * 11.7
51,881.6 = m * 48.8943
mass = 1,061.1 g
does this look better?

aaronq · Answer

yep!

anonymous · Answer

cool thanks for your help

aaronq · Answer

no problem