Question

Find the general solution of y'+ay=0.

Answer 1

it is separable :
\[\large \begin{array} \\ \dfrac{dy}{dx} &= - ay \\ \dfrac{dy}{y} &= -a dx\\ \int \dfrac{dy}{y} &= \int -a dx \end{array}\]

Answer 2

integrate ^^

Answer 3

Let me try. Please don't go.

Answer 4

okie

Answer 5

So it's ln abs(y)=-ax+C where abs means absolute value of, y=e^(-ax), right?

Answer 6

yep ! below form looks better :

\[\large y = Ce^{-ax}\]

Answer 7

Thank you!

Answer 8

np :)