Question

help medal + fan

Is the real part of every non-trivial zero of the Riemann zeta function 1/2?

Answer 1

yeah :o

Answer 2

i think i solved this before , but cant find my notes :'(

Answer 3

yeah

Answer 4

ok ty guys wish I could give 2 medals

Answer 5

i remember we did it together

Answer 6

spam me with medals :P
then ill show u

Answer 7

im pretty sure we can use induction here

Answer 8

\[\large\square\]

Answer 9

yeah somy together in univ , do u remember tht day

Answer 10

i think euclid showed this with triangles back in the day using newton's method

Answer 11

yes it was a nice rainy day ( ˘ ³˘)❤

Answer 12

@iambatman @Astrophysics @ganeshie8 @ParthKohli

Answer 13

i think @abb0t can help

Answer 14

good idea dan

Answer 15

@preetha'shusband

Answer 16

yeah we discover amazing thing :o
we will donate with the money to OS organization :D

Answer 17

@goformit100

Answer 18

@KL-RC

Answer 19

@study100

Answer 20

@superhelp101

Answer 21

@beccaboo333

Answer 22

*

Answer 23

interesting...

Answer 24

@jim_thompson5910

Answer 25

yeah , but me and somy reached to something :D

Answer 26

good job ty

Answer 27

yeah we are so smart ( ˘ ³˘)❤

Answer 28

ikr <3

Answer 29

Like guys..Has Anyone Really Been Far Even as Decided to Use Even Go Want to do Look More Like?

Answer 30

Even.

Answer 31

yes

Answer 32

no

Answer 33

If there was a scale from 1 to even i can't.

Answer 34

You've got to be kidding me. I've been further even more decided to use even go need to do look more as anyone can. Can you really be far even as decided half as much to use go wish for that? My guess is that when one really been far even as decided once to use even go want, it is then that he has really been far even as decided to use even go want to do look more like. It's just common sense.

Answer 35

niether

Answer 36

im just gonna cry bahahahahaha

Answer 37

yes kai even.

Answer 38

ODD

Answer 39

i can't even

Answer 40

something really smart

Answer 41

its just too smart for my tiny brain.even.

Answer 42

Well we could try to see about orthogonalizing the hamiltonian vectors, while making sure we normalize them before integrating with respect to the determinant of the Cayley matrix. Of course, we will have to consider that there will be n factorial paths to optimizing the square root of the binomial expansion for our set. Then again, I may not be completely right here since I've not worked with the zeta function only the gamma and delta functions.

Answer 43

i wonder.......
what...
did..
i.
just
read...( ˘ ³˘)❤

Answer 44

kai<3 that was so smarty

Answer 45

too smart that my brain just exploded ( ˘ ³˘)❤

Answer 46

wait!!! Actually we just need to see that for all epsilon less than zero there exists at least one y such that the limit does not exist. The limit of course meaning as we do a keyhole integration along the geometric series of singularities that exist in the topology of the holomorphic function itself. Hmm... Knot theory holds the answer of course.

Answer 47

true . . .

Answer 48

the answer is
love...

Answer 49

awwwww i love you too <3

Answer 50

awwww ( ˘ ³˘)❤

Answer 51

True. Well, according to Stephen- http://www.wolframalpha.com/input/?i=real+part+of+roots+of+zeta+function

He gives 1/2 but doesn't explain why? Hmmm...