Question

Simplify the expression.

(csc^2xsec^2x)/(sec^2x+csc^2x)

Answer 1

replace cosec x by 1/(sin x) and sec x by 1/(cos x) and then simplify u may get 1 as the final answer

Answer 2

Okay I did and got, (1/sin^2)(1/cos^2x) all over 1/cos^2x + 1/sin^2x

Answer 3

I get confused from there

Answer 4

@matricked What do I do from here?

Answer 5

= (1/sin^2)(1/cos^2x) / ( 1/cos^2x + 1/sin^2x )
= (1/sin^2)(1/cos^2x) / ( ( sin^2x + cos^2x )/ (cos^2x *sin^2x) )
= (1/sin^2)(1/cos^2x) * (cos^2x *sin^2x) / ( ( sin^2x + cos^2x ) )
=1

we know sin^2x + cos^2x = 1

Answer 6

On the second row, how did you get rid of the 1 over the denominators in 1/cos^2x+1/sin^2x?

Answer 7

Any help please?

Answer 8

1/cos^2x+1/sin^2 = ( sin^2x + cos^2x )/ (cos^2x sin^2x) ) [taking LCM and adding]

Answer 9

I'm still confused

Answer 10

It just looks like you made the denominator into the numerator and vice versa

Answer 11

can you calculate (1/2+ 1/3)

Answer 12

Yes, 5/6

Answer 13

did you ever gt in btwn like (3+2)/(3*2)

Answer 14

What?

Answer 15

does it looks like you made the denominator into the numerator and vice versa

Answer 16

similar steps are done for
1/cos^2x+1/sin^2x = ( sin^2x + cos^2x )/ (cos^2x sin^2x) )

Answer 17

No

Answer 18

OHHH, thank you

Answer 19

ok what abt solving 1/a + 1/b

Answer 20

I got it now, I finally understand now, I feel really dumb

Answer 21

you should ask if you don't understand