Question

In a rectanglular coordinate system, what is the area of a triangle whose vertices whose vertices have the coordinates (4,0), (6, 3) adn (6 , -3)

Answer 1

area of triangle is = 1/2 * base * height
please plot the vertices on a graph it will be easy to calculate

Answer 2

here height will be 2 units and base will be 6 units
so arae will be 6 square units

Answer 3

hey akankha,This question can be solved by calculating the eucleadian distance between the points x and y so can you care to specify the vertices(Base,hpo,perpendicular)..please rporvide a simple diagram

Answer 4

here's the way:

lets say two vertices of the base be \[V _{B1} \] and \[V _{B2}\]

where\[ V_{B1} = [x _{1},y _{1}]\]
\[V _{B2} = [x _{2},y _{2}]\]



Now calculate the length of base:

\[Base=Distance \between V_{B1} and V _{B2}\]

Distance between two points in cartesian/euclidean space : =

\[D = \sqrt{(x _{1} - y _{1})^{2} + (x _{2} - y _{2})^{2}}\]

by using that formula we can calculate the length of base and height .

then you can plug them into :

\[Area \Delta = \frac{ 1 }{ 2 } \times base \times height \]

And voila,there comes your area of the triangle.

NOte:you have to figure it out how to calculate the length of height yourself(I already equipped you with the artillery required(believe me it will be fun))