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Convert 84 g of CaO to moles. Use: \(\sf moles=\dfrac{mass}{Molar~mass}\) Next, multiply the moles by the standard enthalpy, \(\sf \Delta H^o = -65.2 ~kJ/mol\). \(\sf \Delta H_{rxn}=(-65.2 ~kJ/mol)*moles~of ~CaO\)
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