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Mathematics 7 Online
OpenStudy (anonymous):

Algebra 2 Help please? I'll give out medals and become fans In a previous algebra 2 problem, it told me to make a two- way frequency table. However, in another question, it said to find the probabilities of P(A ∩ B) and P( A ∪ B) and compare. Extremely confused :\ I'm not really sure what to put for A and B either

OpenStudy (anonymous):

OpenStudy (anonymous):

@ranga

OpenStudy (anonymous):

@mathmale

OpenStudy (anonymous):

@nikato ?

OpenStudy (anonymous):

please helllllpppp :(

OpenStudy (anonymous):

Karp

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

Karp!

OpenStudy (anonymous):

ok...

OpenStudy (anonymous):

google magikarp

OpenStudy (anonymous):

how is Pokemon even remotely related to this?

OpenStudy (anonymous):

pokemon relates to everything

OpenStudy (anonymous):

@Hero ?

OpenStudy (anonymous):

anyone?

OpenStudy (phi):

ok, we have a table. But what is the question?

OpenStudy (anonymous):

The question is: Compare P(A∩B) with P(A∪B), and explain what each probability means in the context of the situation and data you collected.

OpenStudy (phi):

and do they define A and B ?

OpenStudy (anonymous):

no, I think they want me to define A and b, but that's where I get stuck; which ones do I pick for a and b?

OpenStudy (phi):

can you take a screen shot of the question along with any info they provide?

OpenStudy (anonymous):

I'm stuck on number 4

OpenStudy (phi):

ok. did you answer part 3? if so, what was the answer?

OpenStudy (anonymous):

For the third question I put P(Person is a male| Person is 'for') for P(A|B) and I got 4/6, and for the P(B|A) I got 4/10

OpenStudy (anonymous):

I'm not sure if that is correct though

OpenStudy (phi):

P(A | B) is 4/6 = ( A \( \cap \) B)/A= 4/ 6= ⅔ (you should simplify) P(B|A) = ( A \( \cap \) B)/A = 4/10 = 2/5 so you did it correctly, except for not simplifying

OpenStudy (phi):

Also, you have defined A and B, so we can do A U B and A ∩ B

OpenStudy (anonymous):

I'm not sure what operation to do for the U and the ∩

OpenStudy (anonymous):

I didn't really use a formula for number 3

OpenStudy (phi):

intersection (the ∩ ) means the number of "events" (in this case, votes) that are both (at the same time) "male" and "for"

OpenStudy (phi):

in other words, the "box" labeled male and for which contains the 4

OpenStudy (anonymous):

so.. would it just be 4/20 or 1/5 then?

OpenStudy (phi):

yes, the Pr ( A ∩ B) is the # of votes in A ∩ B divided by the total number of votes. 4/20 = 1/5

OpenStudy (anonymous):

Thank you so much!! What does the U symbol mean though? I think it's called union but i'm not sure what to do with it

OpenStudy (phi):

union means all events that are either in A or B (but we don't double count)

OpenStudy (anonymous):

so... since intersection is 4/20, what exactly would i do with A and B? Some of my textbooks say that I have to do the P(A) * the P(B) and others say that P(AUB) = P(A) + P(b|A)

OpenStudy (phi):

in this case, we can label each "box" that is in A or B in other words, if a box is "male" or if a box is "for", mark it. How many boxes are marked ?

OpenStudy (anonymous):

Three boxes are marked?

OpenStudy (phi):

yes. now add up the votes in those 3 boxes. that represents A U B divide by the total votes (20) to get the Pr( A U B)

OpenStudy (anonymous):

3/5 or 0.6?

OpenStudy (phi):

? what do the 3 boxes add up to ?

OpenStudy (anonymous):

4+ 6+ 2 = 12

OpenStudy (anonymous):

Is it wrong?

OpenStudy (phi):

ok, yes that is correct

OpenStudy (phi):

If you want to use a formula notice Pr(A) = 10/20 and Pr(B)= 6/20 if we add them we get 16/20 *but we double counted* the box with 4 in it (male and for) so we adjust by subtracting off the 4/20 which happens to be Pr(A \( \cap\) B) so Pr(AUB)= Pr(A)+Pr(B) - Pr(A ∩ B)

OpenStudy (anonymous):

Thank you so much!! You helped me understand this better than anyone textbook could!!

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