help!! oxidation numbers!! AgNO3 + KI ==> AgI + KNO3 2PbS + 3O2 ==> 2PbO + 2SO2
Do you have the rules in front of you now?
yeah but I'm still really unclear on them
Ok. Let's start with KI.
K is in group 1, so its oxidation number is 1.
Make sense?
yep
does that make I -1?
Sweet. Yup!
and am I correct saying NO3 is -1 so Ag is +1?
Yes, the charge on NO3 is -1, so the charge and oxidation number for Ag is +1. :)
Can you find the rest of the oxidation numbers for AgNO3?
there's more? @JoannaBlackwelder
Yup, you just found the oxidation number for Ag. You still have N and O to find.
wait which side are you talking about? so far I have: Ag: +1 NO3: -1
oh and K: +1 I: -1
Those are the charges, but for oxidation numbers, each element gets its own oxidation number.
KI is good. :)
ohhhh ok so what is NO3 then?
Oxygen is always -2 (unless it is a peroxide, which it is not).
oh ok
So, the N has to be +5 for the NO3 ion to add to -1.
why? what would ag be?
Ag is +1 because it is bonded to the NO3 ion which has a charge of -1.
oh ok
oh ok I see where you got the +5 now
what about the other side? How can I tell?
:)
@JoannaBlackwelder
Try the KNO3 first.
well is NO3 still -1?
That is the charge of the ion, but not the oxidation number.
how do I know if anything has changed then?
O is still -2
always? no matter which side of the reaction?
Unless it is a peroxide (which is almost never). :)
got it! ok so what else stays the same?
Hydrogen (H) has oxidation number +1 with nonmetals and –1 with metals. Fluorine (F) only has oxidation number, –1. Oxygen (O) has oxidation number -2, except in peroxides where it is –1. The alkali metals (Group 1) have 1 valence. This is lost to achieve noble gas configuration, and so alkali metals have oxidation number +1. The alkaline earth metals (Group 2) have 2 valence electrons, and so have oxidation number +2. Group 13 elements have 3 valence electrons, and so have oxidation number +3. Group 14 elements have 4 valence electrons. They tend to have oxidation number +4 with nonmetals and oxidation number –4 with metals and H. The pnictogens (Group 15) has 5 valence electrons. They gain electrons to achieve noble gas configuration, so they usually have oxidation number –3. The chalcogens (Group 16) have 6 valence electrons, and typically have oxidation number –2. The halogens (Group 17) have 7 valence electrons, and so have oxidation number –1. In the transition metals Ag has oxidation number +1, Zn and Cd have oxidation number +2, and Sc, Y and La have oxidation number +3. Groups 14 to 17 have several oxidation number when they form oxoacids.
oh boy ok
so since I is in the 17th group does it always have an oxidation number of -1?
I know it is a lot, but it is honestly better to have a lot of rules than a little.
Almost always.
true true
Unless it is in a oxoacid (which is almost never) http://chemteacher.chemeddl.org/services/chemteacher/index.php?option=com_content&view=article&id=154
haha so many exceptions!
Yeah, but they are pretty uncommon. :)
ok so in this case, I is still -1 and K is still +1
Right. :)
great. and N is -3?
because N changed in the last one depending on what the other numbers were
How do you get that?
because N is in the 15th group
"The pnictogens (Group 15) has 5 valence electrons. They gain electrons to achieve noble gas configuration, so they usually have oxidation number –3."
They do usually have oxidation number -3, but the oxidation numbers also have to sum to 0 since the compound is neutral.
yeah that's what I thought which is yet another reason for me to be confused. Ok so how do I find it?
I need to find Ag and N in the products
Same way as last time.
NO3 has charge of -1 and O has oxidation number of -2.
So, N has to be +5 to make them sum to -1.
why -1?
Because NO3 has charge -1
why does the sum have to be -1?
Because the oxidation numbers have to sum to the charge of the molecule.
hmm ok
How about Ag in the products?
it still has a +1 charge because I has a -1 charge and the charge of AgI is 0
right?
yup :)
awesome! Ok let me try the last one on my own and I'll tell you what i get
Sounds good. :)
2PbS + 3O2 ==> 2PbO + 2SO2 Pb: +4 S: -4 O: -2 ==> Pb: +4 O: -2 S: +4 O: -2
Elements are always 0.
The rules are for compounds.
oh right so Pb: +4 S: -4 O: 0 ==> Pb: +4 O: -2 S: +4 O: -2
How did you gt Pb: +4, S:-4 in the reactants.
pb is in the 14th and it is paired with a nonmetal so it should be +4 right?
Looks right to me :)
But in the products, Pb would be 2+ because O is -2.
Pb just tends to be 4+ but O is always 2-.
gotcha! so it's Pb: +4 S: -4 O: 0 ==> Pb: +2 O: -2 S: +4 O: -2
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