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Mathematics 7 Online
OpenStudy (oleg3321):

please can someone help will medal

OpenStudy (oleg3321):

In a biological lab, the cell growth rate of two different organisms is tracked and recorded each week. Given the growth rate, the number of organisms can be determined using the following equations: s(x) = 100 + 23x m(x) = 90(1.2x) Complete the table of values. x 100 + 23x 90(1.2x) 0 1 2 3 4 5 Use the table to determine at approximately which point the number of cells will be the same for each organism. Graph the system of equations and show the point of intersection. Explain what the points graphed for each line represent. Explain how you can determine the solution to the equation 100 + 23x = 90(1.2x) using the graph from part c. Find the point(s) of intersection, and explain what the intersection represents in the context of the problem.

OpenStudy (oleg3321):

@Hero

OpenStudy (oleg3321):

@kade_sonix @shamil98

OpenStudy (oleg3321):

@Hero

OpenStudy (anonymous):

what is this

OpenStudy (oleg3321):

algebr 1. system of equations

OpenStudy (oleg3321):

@campbell_st

OpenStudy (campbell_st):

so how far have you gotten with the table...?

OpenStudy (mony01):

don't you just plug in those numbers for x to make the table

OpenStudy (oleg3321):

havent even begin. i really need help with it

OpenStudy (campbell_st):

can I check, is \[m(x) = 90(1.2^x)\] or \[m(x) = 90(1.2x)\]

OpenStudy (anonymous):

@JoannaBlackwelder

OpenStudy (oleg3321):

its m(x)=90(1.2^x)

OpenStudy (campbell_st):

ok.. and S(x)= 100 + 23x no power of x....is that correct...

OpenStudy (oleg3321):

ya

OpenStudy (campbell_st):

ok... so substitute x = 0 into each equation \[s(0) = 100 + 23 \times 0 = 100\] and \[M(0) = 90(1.2^0) = 90\] so you need to put the values s(0) = 100 and m(0) = 90 into the table next repeat the process with x = 1 s(1) = 100 + 23 x 1 = 123 \[m(1) = 90(1.2^1) = 108\] hope it all helps put those values into the table repeat the process from x = 2 s(2) = 100 + 23 X 2 = 146 \[m(2) = 90(1.2^2) = 129.6\] keep repeating the process for each vallue of x in the table... then plot the points.. each point gives the population s(x) or m(x) for different time values so (0, 100) means that for s(x) the initial population of organisms was 100. (1, 123) after 1 time period the population grew to 123... same thing for m(x) the solution to the problem is the point where the 2 lines intersect. This will be the time period when the populations of organisms is the same.

OpenStudy (oleg3321):

okay but how about part b c d e f

OpenStudy (campbell_st):

read the notes for B, C, D and E

OpenStudy (campbell_st):

but before you answer C, D, E plot the curves you can use https://www.desmos.com/calculator

OpenStudy (oleg3321):

ok i just did. and they really confuse me. can you please tell me how to get the answeres

OpenStudy (campbell_st):

ok... so plot the point or use graphing software to get the curves

OpenStudy (oleg3321):

i dont know how to use it . soory. can you do it for me.

OpenStudy (oleg3321):

please dont give up on me @campbell_st i really need to do this

hero (hero):

@oleg3321, you have to be able to do some of the work on your own. It's not the responsibility of helpers here to do ALL the work for you. If that's what your intent is, then yahoo answers may be more appropriate for your needs.

OpenStudy (oleg3321):

no i actually want help and thats why im answering to the questions he askes.

OpenStudy (oleg3321):

@campbell_st can you still help me please

OpenStudy (campbell_st):

ok... so here is the graph... complete with the points

OpenStudy (oleg3321):

so to finish the graph it would be all those points in the graph right?

OpenStudy (oleg3321):

@campbell_st

OpenStudy (campbell_st):

well it you plot the points from the table... and then put then on the graph... you get the graphs I've posted.

OpenStudy (oleg3321):

sorry im kinda slow right now.so then,what would be th answer for a . @campbell_st

OpenStudy (campbell_st):

for (a) you would need to complete the tables... which requires you to substitute x = 0 into both equations and record the answers then x = 1 into both equations and record the answers then x = 2 into both equations and record the answers... repeat the process upto x = 5 thats what part (a) build the table of values then approximate the point where the values are equal.

OpenStudy (oleg3321):

|dw:1407222858101:dw|

OpenStudy (oleg3321):

@campbell_st is that correct

OpenStudy (campbell_st):

well you're 1st value for m(x) is incorrect if \[m(x) = 90(1.2^x)\] then \[m(0) = 90 \times 1.2^0 = 90\]

OpenStudy (oleg3321):

so i did every thing wrong?

OpenStudy (oleg3321):

@campbell_st

OpenStudy (campbell_st):

nope.. just m(0) the rest seem ok

OpenStudy (oleg3321):

|dw:1407223392942:dw|

OpenStudy (oleg3321):

did you mean like that

OpenStudy (campbell_st):

thats correct

OpenStudy (campbell_st):

go back and look at the file I attached... its the graphs of both curves... and the points in your table are shown on each individual curve....

OpenStudy (oleg3321):

it says "Use the table to determine at approximately which point the number of cells will be the same for each organism." how do i find that @campbell_st

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