Question

Hi can someone help me with a Calculus question. thanks

Answer 1

When t=4, h = 3200
tanθ = (3200/150), so θ = 1.52396 radians
tanθ = h / 150
Differentiate with respect to t:
sec²θ (dθ/dt) = (1/150) (dh/dt)
sec²(1.52396)(dθ/dt) = (1/150) (400(4))
dθ/dt = .......?

Answer 2

Make sure your calculator is in radians. What do you get?

Answer 3

0.023?

Answer 4

Yep! You're correct!!:)

Answer 5

but the value of sec^2 is what? thanks

Answer 6

What do you mean? You already have the answer:) You want to know what \[\sec^2\] ? Want the exact value?

Answer 7

the answer was in the back of the book. its just the process i don't understand.

Answer 8

Doesn't your book explain?

Answer 9

i understood the first part but after "differenciate with respect to t" i got confused

Answer 10

is that it?

Answer 11

You're supposed to differentiate. Do you know what that means? Yes! That's what it is.

Answer 12

oh ok

Answer 13

so it was only a different way that i used

Answer 14

sec²θ (dθ/dt) = (1/x) (dh/dt) ?

Answer 15

Yea. But you still got the answer. Yes. I agree. There's many ways to solve this just to get to an answer. What's the other equation? You don't understand?

Answer 16

but after i plugged in the numbers like u did i got confused with the sec^2 as i don't know its value to find (dθ/dt)

Answer 17

But you know, after all you're looking for d(theta). Ok. I think I made a mistake accidentally by putting it in. I've just realized that. Sorry about the confusion.

Answer 18

ok so using my own equation above sec²θ (dθ/dt) = [x(dy/dt)-y(dx/dt)/(x) and filling the numbers i get sec²θ (dθ/dt) = [(150)(1600)-0/(150) now how do i move on from here