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(1+i)^-3
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I just need the answer what you are getting
|dw:1407236690493:dw|
\[\Large \frac{1}{(1+i)^3}*\frac{(1-i)^3}{(1-i)^3}=\frac{1-3i-3+i}{2^3}\] \[\Large \frac{-2-2i}{2^3}=- \frac{1+i}{4}\]
yes, i think if i rationalise my fraction i will get it
Yup.
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An alternate way is to normalize (1+i) which should be pretty straightforward to see that this is a 45 degree angle, so \[\Large (1+i)=\frac{2}{\sqrt{2}}e^{i \pi/4}\] Then you can more easily plug this in as well.
cool!
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