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Find the area of the region bounded by
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\[y = x ^{4} - 4x ^{2} and y = x ^{3} -4x\]
draw them out first find the intersections, consider which graph is on top/ bottom on each interval take integral for each of them add them together.
This is the graph, so that in [-2,0] \(x^3-4x\) on top and \(x^4 -4x^2\) is in bottom The area of this interval is \[\int_{-2}^0 (x^3-4)-(x^4-4x^2) dx\] solve for it, you have the results of this interval, let say r1 Do the same with the second interval [0,1]. Pay attention, at this interval, x^4-4x^2 is on top. Do the same with 3rd one and 4th one, Add them together
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