Question

HELLLLLP!!!

Answer 1

both PLEASEEEEEE

Answer 2

Doesn't the first one kinda look like a quadratic?

Answer 3

\[\large sin^2(x) + sin(x) - 2 = 0\]
\[\large (sin(x) + 2)(sin(x) - 1) = 0\]

Lets solve that...either sin(x) = 2 (which s not possible...or sin(x) = 1

when does sin(x) = 1?

Answer 4

whats the naswer for which one?

Answer 5

Let\[\sin (x)= y\]
Then you get\[y ^{2}+y-2=0\]
Find for y first end for x.

Answer 6

okay yes whats the final answer?

Answer 7

If looking at my approach, when does sin(x) = 1 what angle measure?

If looking at Zekarias approach, solve that quadratic

Answer 8

whats the final answer????? Im really tight for time please!!

Answer 9

HELPPPPPP!!!!!

Answer 10

and this one!

Answer 11

really! @superhelp101 @princeharryyy

Answer 12

@Katieholmes Please don't look for answers, please get involved in the solving process. Just answers won't help you in anyway.

Answer 13

sin^2x+sinx-2=0;
sin^2x+2sinx-sinx-2=0;
(sinx+2)(sinx-1)=0 =>
sinx=-2 or sinx=1 =>
sinx=-2 doesn't exist therefore sinx = 1 =>x=90deg @Katieholmes

Answer 14

2nd ques=>
(1/2+1/2)/(sqrt(3)/2 * sqrt(3)/2) =>4/3
@Katieholmes

Answer 15

awesome! LIfe saver really!

Answer 16

tnks @Katieholmes u r welcome !!!

Answer 17

tan 63 deg = height/20 =>
height = 39.25 rounded to 39.3 as answer @Katieholmes