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Physics 10 Online
OpenStudy (anonymous):

An object 4.56 centimeters tall is placed 78.3 centimeters in front of a diverging lens. The lens has a focal length of 45.9 centimeters. How tall is the image? How far from the lens is the image? Is the image virtual or real? Is it upright or inverted? I really don't understand and could use a walkthrough. will medal and fan

OpenStudy (masumanwar):

The image formation in the lens have a formula as 1/u\[1/u +1/v=1/f\]

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