serious simplifying complex fractions here!! 3 2 --- + --- x x+2v ------------------ 3 2 ---- - ---- x+2 x
scratch that random v
yes, I knew that !!
\(\Huge\color{black}{ \frac{\frac{3}{x} + \frac{2}{x+2} }{\frac{3}{x+2} + \frac{2}{x} } }\) like this ?
yes
\(\Huge\color{black}{ \frac{\frac{3\color{darkgoldenrod}{\times (x+2)}}{x\color{darkgoldenrod}{\times (x+2)}} + \frac{2\color{darkgoldenrod}{\times x}}{(x+2)\color{darkgoldenrod}{\times x}} }{\frac{3\color{darkgoldenrod}{\times x}}{(x+2)\color{darkgoldenrod}{\times x}} + \frac{2\color{darkgoldenrod}{\times (x+2)}}{x\color{darkgoldenrod}{\times (x+2)}} } }\)
can you tell me WHY am I doing this ?
common denominator
yes common denominator, tell me what you get after multiplying ad adding the fractions on top and bottom, please.
\[5x+6 \over x(x+2)\]
\[5x+4 \over x(x+2)\]
Yes, the first one is the numerator, and the second is the denominator.
\(\Huge\color{black}{ \frac{\frac{5x+6}{(x(x+2)} }{\frac{5x+4}{x(x+2)}} }\) is the same thing as, \(\LARGE\color{black}{\frac{5x+6}{(x(x+2)} \div\frac{5x+4}{x(x+2)} }\) and knowing that \(\LARGE\color{black}{\frac{A}{B} \div\frac{C}{D}=\frac{A}{B} \times\frac{D}{C} }\) can you tell me, what cancels out ?
x(x+2)
GOod ! And your answer is ?
\[5x+6 \over 5x+4\]
Yup :)
thank you!
Anytime !
Join our real-time social learning platform and learn together with your friends!