Question

Quadratic formula on the docket! Any math lovers able to make sense of this problem for me?
6x^2-9x+1=0
I'm supposed to solve using the quadratic formula which is messing me up because I know how solve by completing the square.

Answer 1

(but also rusty on the completing the square process)

Answer 2

\[6x ^{2}-9x +1=0\]
\[3x(2x-3) +1=0\]
\[3x(2x-3)=-1\]
\[2x-3=\frac{ -1 }{ 3x }\]
\[\frac{ 2x }{ 1 }+ \frac{ 1 }{ 3x }=3\]
\[2\frac{ 1 }{ 3 }x=3 \]
\[x=3\div \frac{ 7 }{ 3 }\]
\[x=\frac{ 9 }{ 7 } =1\frac{ 2 }{ 7 }\]
I hope I am correct

Answer 3

@Mokeira
\[\frac{2x}{1} + \frac{1}{3x} \ne 2 \frac{1}{3} x\]

Answer 4

@LaylaJ
the quadratic formula and completing the square are same thing, the formula is derived using completing the square

Answer 5

quadratic formula is easy because its already solved for you, just plug in the numbers

Answer 6

Ok, so I already know the basics of the qf since I know how to complete the square?

Answer 7

yes

Answer 8

@dumbcow... true. i messed up there

Answer 9

Guess I'll go back to my math book with renewed confidence. Thanks!

Answer 10

\[x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\]

a = 6
b = -9
c = 1

Answer 11

lightbulb! :)

Answer 12

Thank you for teaching me!