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The equation shows one mole of ethanol fuel being burned in oxygen. Convert the energy released into its equivalent mass. C2H5OH(l) + 3 O2(g) Æ 2 CO2(g) + 3 H2O (l) ΔH = -1418 kJ/mol
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Well sense we are doing an combustion we assume that the only work done on the system is volume work and we can write up the following: ΔU=q+w w=0 q=ΔH Here is U, the internal energy, q the process of heat, w the process of work and delta H the change in entropy. We can here use Einstein's relation between mass and energy: E=mc2 We isolate for the mass, m; m=Ec2 Where: E=ΔU=ΔH ..........Hope it helps.............
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