Factor the four-term polynomial. pq - 2r + pr - 2q. I don't understand how to do it, being stuck under a truckload of summer school work because I moved and missed valuable material. Walk throughs are preferable.
You might have to experiment to factor this. The trick is to identify the terms that have something in common and to group them. suggestion: leave the 1st and 4th terms where they are, and interchange the 2nd and 3rd terms. Write out your result here.
Pq - pr + 2r - 2q? Or do the signs not retain placement? @mathmale
Each term retains (keeps) its sign.
Thus, pq - 2r + pr - 2q becomes pq + pr - 2r - 2q
Agree or disagree?
Agree, it seems easier in correlation to the signs etc as well.
Now interchange the first 2 terms.
So. Pr + pq - 2r - 2q?
Now which letter do the first 2 terms have in common? which numeral have the 2nd 2 terms in common?
After you've answered those questions, go ahead and factor the 1st 2 terms and then factor the right 2 terms.
Well that's p, and 2 respectively, but I'm not even sure how to factor becaus dive lost so much school time.
Well, the first two terms both have p in them, don't they?
Yes
Then the first two terms of Pr + pq - 2r - 2q factor to p(r+q). Please factor the second two terms. - 2r - 2q factor to ... ?
Q + 2?
Please look at - 2r - 2q and identify what it is (what factor) the two terms have in common.
- 2
Right. So, factor out that -2. rewrite - 2r - 2q in factored form.
(q-r)?
What happened to the -2? You have to keep it.
You've correctly identified -2 as a factor. What's left, after you've divided - 2r - 2q by -2?
- 2r - 2q ---------- = ? -2
Wouldn't it just be 1r - 1q?
- 2r - 2q factors as follows: -2(r+q). Make certain you understand this before we move on.
Pr + pq - 2r - 2q can be re-written as p(r+q) + what?
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