Question

Can somebody PLEAAAAASSEE help me with this problem???

Answer 1

\[\sum_{m=1}^{5}(4m ^{2}+4)\]

Answer 2

What do you get for the first term?

Answer 3

I don't remember how to do this >_<

Answer 4

What is the value of m in the first term?

Answer 5

1

Answer 6

Okay plug that into the formula and what do you get?

Answer 7

4(1)^2+4
4+4=8

Answer 8

Okay that is the first term. Since this is a capital sigma question, what will you do with that when you get the next term?

Answer 9

8+20+40+68+104+148=

Answer 10

388

Answer 11

Is that the answer?

Answer 12

One too many terms. From one to five is five items.

Answer 13

but isn't that the sum equation?

Answer 14

[4(1)^2+4]+[4(2)^2+4]+[4(3)^2+4]+[4(4)^2+4]+[4(5)^2+4]+[4(6)^2+4]= 8+20+40+68+104+148= 388

Answer 15

Thr xum says from m=1 to m=5. That is 1, 2, 3, 4, 5 terms.

Answer 16

Oh ok. I see what you are saying

Answer 17

What about this equation? \[5(18^{6x})=26\]

Answer 18

Solve the equation. Round the answer to the nearest ten-thousandth.

Answer 19

@LarsEighner