Question

help please...

Answer 1

Multiply the fractions and reduce to lowest terms

Answer 2

wow its already factored for you... ok start by cancelling like terms

Answer 3

thats where i get confuse..do i cancel the 3 and x and 1?

Answer 4

??
no dont separate the factors,
for example there is a (x+3) on top and a (x+3) on bottom so the factor (x+3) cancels

Answer 5

i need to see it so i can understand it

Answer 6

(x+1)(x+1)(x-3)/((x+1)(x+5)(x+3)) - (x+3)(x+3)(x+5)/((x+1)(x+5)(x+3))
make the denominator same in both the questions and solve the numerators to get the above factors

Answer 7

ok

Answer 8

this is what i got

Answer 9

what were ur num after solving

Answer 10

\[[x+3](x+3)(x+5)+[x+1](x+1)(x-3)\]

Answer 11

\[\frac{(x+1) (x-3)}{(x+3) (x+5)}-\frac{x+3}{x+1}=\frac{6}{x+3}-\frac{16}{x+5}-\frac{2}{x+1} \]

Answer 12

\[[x ^{3}-x ^{2}-5x-3]+[x ^{3}+11x ^{2}+39x+45]\]
open up the brackets and simplify
\[10x ^{2}+34x+42\]

Answer 13

That is the answer

Answer 14

i did everything yall showed me
problem...the answer i got isnt in the options..so im doing something wrong
dont think im trying i am i jst suck at algebra badly

Answer 15

*dont think im not trying i am

Answer 16

check out the equation in the ques again

Answer 17

wow guys this isn't that complicated

the (x+3) cancels , the (x+1) cancels
leaving

--> x-3/x+5

Answer 18

ok i understood tht now.. i saw what i did wrong i didnt cancel out the x+3

Answer 19

@robtobey , this is multiplying not subtracting
(i know the picture is deceiving)