Question

The length of a rectangle is 2 foot less than 3 times its width. Find the dimensions of this rectangle if the area is 96 square feet.

Answer 1

@nincompoop please help

Answer 2

Ok...so
start with the equation for area: LW= area
You are given that L=3W-2
So substiture 3W-2 in for L

you will get LW=96(area)
(3W-2)W=96 expand
3W(W) -2W=96
3W^2-2W=96
3w^2-2W-96=0 solve.......

Answer 3

I have gotten that far on my own, but I don't know what to do next. I don't understand how to factor it out. @aryandecoolest

Answer 4

let width be w
length= 3w-2
A=l*w
96=w(3w-2)
\[96=3w ^{2}-2w\]
\[3w ^{2}-2w-96=0\]

Answer 5

Thank you, but I have gotten that far on my own I just don't know how to factor with the 3 infront of the w. Can you please help me more? @Mokeira

Answer 6

ok...so
here's what I got......(w-6)(3w+16), then set each term to zero and solve for w, these will be your solutions

Answer 7

THANK YOU! I got w=6 and w=-16/3 @aryandecoolest

Answer 8

16 ans

Answer 9

Hope i helped a bit...!!
yeah anytime )

Answer 10

@klovic