Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Can someone help me pls? Medal AND fan! Sketch a graph of the following function. f(x)=\frac{1}{-1x+2} Where are the vertical asymptotes?

OpenStudy (campbell_st):

so is the equation \[f(x) = \frac{1}{-x + 2}\]

OpenStudy (anonymous):

yup

OpenStudy (campbell_st):

ok.. so the vertical asymptote exists when the denominator is zero so solve -x + 2 = 0 this will be the asymptote

OpenStudy (anonymous):

but how? i dont really understand it...o.o

OpenStudy (campbell_st):

ok... so if a fraction has a zero denominator its undefined... or... you can't divide anything by zero.... there is no answer.... so that is what you are looking for the value of x that makes the denominator zero

OpenStudy (anonymous):

ok, so i just graph the asymptote?

OpenStudy (campbell_st):

show the asymptote as a dotted line and then graph the functions... its hyperbolic and it looks like

OpenStudy (anonymous):

lol alright, i see. thank you! :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!