Question

Given the enthalpies of reaction below, determine the enthalpy change for the reaction: N2O (g) + NO2 (g) arrow 3NO (g).

N2 (g) + O2 (g) arrow2NO (g)


ΔH = +180.7 kJ

2NO (g) + O2 (g) arrow2NO2 (g)


ΔH = -113.1 kJ

2N2O (g) arrow2N2 (g) + O2 (g)


ΔH = -163.2 kJ
Answer

155.6 kJ

130.6 kJ

311.3 kJ

65.3 kJ

Answer 1

@ganeshie8 @texaschic101 @nincompoop

Answer 2

@Somy

Answer 3

SOMY!!
Thanks the Gods, please help.

Answer 4

hmm well firstly change these reactions to the way you want them to be

Answer 5

yeah...how do I do that?

Answer 6

N2 (g) + O2 (g) arrow2NO (g)


ΔH = +180.7 kJ

alright so here we have enthalpy change of formation of NO

in the main reaction its 3 but here its 2 (coefficient meaning)

i believe you can just do it like this
+180.7 = 2
X= 3
X= +180.7*3/2
X= new enthalpy change to get 3 of NO

[not sure tho]

Answer 7

2NO (g) + O2 (g) arrow2NO2 (g)


ΔH = -113.1 kJ

alright here enthaply change is given for 2 of NO2 while in main reaction we have only 1 NO2
so if

-113.1 kJ = 2
X= 1
X= -113.1/2
X= new enthalpy change of formation of 1 NO2

Answer 8

Nm, I think I got the answer
can you help with this one tho?
hich of the following is an example of objects in thermal equilibrium?
Answer

ice warms in a glass before you can pour soda into the glass

a spoon in a cup of hot soup absorbs heat

a pan is placed on a stove burner and becomes hot

two panes of glass are at the same temperature as air trapped between them

Answer 9

I think it's d

Answer 10

2N2O (g) arrow2N2 (g) + O2 (g)


ΔH = -163.2 kJ

in this reaction its rather formation of 2N2 (g) + O2 (g)
but we need the opposite
so if for forming 2N2 (g) + O2 (g) we enthalpy change is -163.2 kJ
that means if we want the opposite effect = we can just change the sign to +163.2 kJ

now the reaction looks like this
2N2 (g) + O2 (g)-> 2N2O (g)
ΔH = +163.2 kJ
again
in the main reaction there are only 1 of N2O but here there are 2 of N2O
so
+163.2 kJ = 2
X= 1
X= +163.2 kJ/2
X= new enthalpy change of formation of N2O (g)

Answer 11

so now you have everything so u can use the formula of Enthalpy change of reaction
Enthalpy change of reaction = Enthalpy change of reactants- Enthalpy change of products

Answer 12

do u think u can do it now?

Answer 13

btw im not sure about the other question
sorry

Answer 14

Wow...thanks a bunch! :D

Answer 15

you are welcome (๑>ᴗ<๑) :)))