Question

Can someone please help me ASAP

Answer 1

I really dont get it

Answer 2

Well...
It says rte of change when n=1 and n=3
So you substitute n for 1 and solve:
\[a _{n}=1(3)^{n-1}\]
\[a _{1}=1(3)^{1-1}\]
\[a _{1}=1(3)^{0}\]
\[a _{1}=1(1)\]
\[a _{1}=1\]

Answer 3

oh ok but isn't 1(3)^0=3?

Answer 4

No because whener you have something to the 0 power it goes to 1

Answer 5

A constant^0 always = 1 unless its 0^0.

Answer 6

So Next You find
\[a _{3}=1(3)^{3-1} \]
\[a _{3}=1(3)^{2} \]
\[a _{3}=1(9) \]
\[a _{3}=9\]

Answer 7

\[Average ROC = \frac{ f(x) - f(a) }{ x - a }\]
Where your rate of change is from a to x.

Your change goes from 1 to 3, so, a is 1 and x is 3.

Solve f(1) and f(3):
f(1) = a1 = 1
f(3) = a3 = 9

Fill in the equation:

\[\frac{ 9-1 }{ 3-1 }\]

8/2 which equals 4.

Average rate of change for your function is 4.

Answer 8

Okay thank you guys so much

Answer 9

i appreciate it