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Either \[\sqrt{2/2}\] or -1
How do you solve? @chrisisdope1
please explain
3π/4 = 3 ×180÷4=135 \(\normalsize\color{blue}{ \sin(180-45)=\sin(180)\cos(45)-\cos(180)\sin(45)=(0)(\frac{\sqrt{2}}{2})-(-1)(\frac{\sqrt{2}}{2})=\frac{\sqrt{2}}{2}}\)
\(\normalsize\color{blue}{ \cos(180-45)=\cos(180)\cos(45)+\sin(180)\sin(45)=(-1)(\frac{\sqrt{2}}{2})+(0)(\frac{\sqrt{2}}{2})=-\frac{\sqrt{2}}{2}}\)
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tan(135) = sin(135) ÷ cos(135) = (√2/2 ) ÷ (-√2/2 ) = -1
I was replying to another question and finishing a college application, sorry for replying late.
hey @am!rah could you explain for me..seems you have understood
what I did here, btw, is another prove for `cos(A)=sin(A+ {π/2} )`
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