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Mathematics 10 Online
OpenStudy (anonymous):

Trapezoids:

OpenStudy (anonymous):

OpenStudy (mikurout):

As AB is parallel to CD. so <A +<D = 180 use this to get the value of <A ,by putting <D = <A/2

OpenStudy (mokeira):

|dw:1407347311270:dw| 180-90=90 90/2=45 a=2(45) I hope its clear

OpenStudy (mikurout):

@Mokeira no, you are wrong.

OpenStudy (mokeira):

@mikurout there are many ways to it..im right

OpenStudy (mikurout):

@Mokeira . so are you saying <A = 90 ?

OpenStudy (mokeira):

theoretically that is wrong but according to the information given, yes

OpenStudy (mokeira):

Actually, i assumed the perpendicular bisects angle A...im wromg. @mikurout

OpenStudy (mikurout):

@Mokeira . That can't bisect <A.

OpenStudy (mokeira):

u r right

OpenStudy (mikurout):

@wgary .Did you get the ans.?

OpenStudy (anonymous):

I'm not sure if we can assume that the trapezoid is like this:|dw:1407347928993:dw| , because I feel like the wording of the problem makes it sound like the trapezoid is like:|dw:1407347978509:dw|

OpenStudy (mikurout):

|dw:1407348038742:dw| This is the trapezoid ,according to your question.Because it is the abcd trapezoid.2nd one is the abdc trapezoid.

OpenStudy (mikurout):

@wgary . Is it clear?

OpenStudy (anonymous):

The solution if it were the trapezoid you described was very obvious, I get understand that one, but I'm pretty sure the trapezoid looks like how I drew it the second time.

OpenStudy (mokeira):

i have not understood

OpenStudy (mikurout):

@Mokeira . what doubt you have?

OpenStudy (mokeira):

how do you find the value of angle A

OpenStudy (mikurout):

@wgary . So will I provide you to the solution for the 2nd diagram?

OpenStudy (mikurout):

@Mokeira In 1st case <A+<D = 180 <A +<A/2 = 180 ( as it is given that <A = 2<D . so <D = <A/2) so (3*<A)/2 = 180 3*<A = 360 <A = 120

OpenStudy (mikurout):

@wgary . For the 2nd case you have <A+<C = 180 so 2<D+3<B = 180 (this is your 1st equation ) Again <B +<D = 180 ( due to AB parallel CD) (this is 2nd eq.) solve these two equation to get the values of <B and <D . then find 2<D = <A .

OpenStudy (mokeira):

@mikurout THANK YOU soooo much. i have understood very well

OpenStudy (mikurout):

@Mokeira . That's sounds good.

OpenStudy (mikurout):

@wgary .What happen to you? Where is your doubt?

OpenStudy (anonymous):

Ah, sorry, went for food, let me read over it :)

OpenStudy (mikurout):

Ok.

OpenStudy (anonymous):

If you try to solve for <D and <B, you get 360 and 180, respectively, which won't work.

OpenStudy (anonymous):

360 and -180*

OpenStudy (mikurout):

Yes,I am looking into it.

OpenStudy (mikurout):

@wgary . From this I have cleared that this condition is valid for 1st diagrm. Because if you will look into the 2nd diagram , you can be sure that <A = 2<D and <C = 3<B , these two conditions couldn't be satisfied simultaneously.

OpenStudy (anonymous):

Ah, okay, then it must be the first diagram, let me try the answer for that.

OpenStudy (mikurout):

yes do it.

OpenStudy (anonymous):

It is correct thank you, sorry for using some extra time

OpenStudy (mikurout):

@wgary . It's ok. You have understood, that is sufficient.

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