Suppose you roll a six-sided die two times hoping to get two numbers whose sum is less than 4. What is the sample space? How many favorable outcomes are there?
12 outcomes?
no your trying to get two nmbers less than the sum of 4
1+1=2 2+1=3 So two favorable outcomes
I mean in total for the two rolls, there's tecnically 12 outcomes. One die has 6 sides, if he used it twice it would be 12?
Since he wants less than 4 there are 3 possibilities, double that it's 6?
The favorable outcomes in this situation are when the two dice rolled at the same time are equivalent to less than 4 in their sum. Only 2 pairs of numbers are less than 4 those being 1+1 and 2+1 so you only have 2 favorable outcomes. As far as possible outcomes, I believe it's significantly more than 12 cause if you pair 1 to every number through 6 thats 6 outcomes, and if you do the same to every other number you get 1 less pair each time
So.. 3 doesn't count? (I'm not good with favorable outcomes) Mind using the formula?
p(event) - Favorable outcomes/Possible outcomes = ?
P(Sum<4)-3/36 i think is the total amount of outcomes P=3/36
Haha whoops logged out, my sister explained it to me and I finally got it. You were right, sorry for being complicated lol.
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