Question

The resultant of two forces acting at right angles is √10N when the same two forces act at 60° the resultant is √13N calculate the forces

Answer 1

For the first case i.e 90°
\(\sf a^2+b^2 +abcos90\)=10

Answer 2

\(\Rightarrow a^2+b^2=10\)

Answer 3

are the two forces equal ?

Answer 4

No they are not equal

Answer 5

i ma not sure about this one. I am getting ab =10/13

Answer 6

I don't know how to proceed further

Answer 7

Ok..ty bro for u effort....i find by tomorrow by asking my lecturer

Answer 8

yeah...u do that...till m trying my best

Answer 9

Here is the image frm the notes .plz make me understand

Answer 10

oh lol !
Solved

Answer 11

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
For the first case i.e 90°
\(\sf a^2+b^2 +abcos90\)=10
\(\color{blue}{\text{End of Quote}}\)

Answer 12

These r the images frm the solution bt i m nt getting it

Answer 13

Yes i was doing a calculation mistake

Answer 14

Now let's see

Answer 15

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
Since cos(90) = 0
=>\(\sf a^2+b^2+0=10\)...
=>\(\sf a^2+b^2=10\)
ok so far ?
\(\color{blue}{\text{End of Quote}}\)

Answer 16

Wan thw image of the question?

Answer 17

no no Question is clear to me....i got the answers...

Answer 18

Now in second case

\(\sf a^2+b^2+2abcos60=13\\Since~cos60=1/2\\=>a^2+b^2+ab=13\)

got it ?

Answer 19

Wait i'll upload a pic of solution

Answer 20

Ok

Answer 21

done..uploading

Answer 22

Ty...nd the value of two forces r 3N nd 1N

Answer 23

Thanks abhisar....

Answer 24

There is one more page wait !