Using the equations and enthalpy values provided, which mathematical expression can be used to determine the unknown enthalpy change represented by x? 3 C + 3 O2 yields 3 CO2 deltaH = x 4 H2 + 2 O2 yields 4 H2O deltaH = - 1144 kJ C3H8 + 5 O2 yields 3 CO2 + 4 H2O deltaH = -2222 kJ C3H8 yields 3 C + 4 H2 deltaH = 104 kJ 104 = (-2222) - [x - (-1144)] 104 = (-2222) - [x + (-1144)] 104 = (-2222) + [(-1144) - x] 104 = (-2222) - [(-1144) - x] @aaronq think you could help please?
I'll give a medal :)
@SolomonZelman Do you think you could possibly help me? I understand if you're busy but I just dont understand this question at all.
I am really bad at chemistry. I used to be very good at it, but I forgot it since 10th grade, and my maximum capability in science is answering some biology questions about Punnet squares. Sorry -:(
@SolomonZelman It's all good. @aaronq do you know any?
yep, i'm workin on it hold up
ok thanks.
This concerns Hess's Law. You have to arrange equations (1) through (3) to (4) to match the top equation (so that everything but what is there cancels out. (1) \( 3 C + 3 O_2 \rightarrow 3 CO_2 ~~~~\Delta H_1 = x\) (2) \(4 H_2 + 2 O_2 \rightarrow 4 H_2O~~~~ \Delta H_2= - 1144 kJ\) (3) \(C_3H_8 + 5 O_2 \rightarrow 3 CO_2 + 4 H_2O ~~~~\Delta H_3 = -2222 kJ\) (4) \(C_3H_8 \rightarrow 3 C + 4 H_2 ~~~\Delta H_4= 104 kJ\) So we reverse (2), and we multiply their enthalpy change by -1 (1) \( 3 C + 3 O_2 \rightarrow 3 CO_2 ~~~~\Delta H_1 = x\) (2) \( 4 H_2O\rightarrow4 H_2 + 2 O_2~~~~ \Delta H_2= 1144 kJ\) (3) \(C_3H_8 + 5 O_2 \rightarrow 3 CO_2 + 4 H_2O ~~~~\Delta H_3 = -2222 kJ\) -------------------------------------------------- (4) \(C_3H_8 \rightarrow 3 C + 4 H_2 ~~~\Delta H_4= 104 kJ\) Then we have \(\Delta H_4=\Delta H_4+\Delta H_4+\Delta H_4\)
i made a mistake, you are to reverse (1) not (2). the rest is fine though, do you get the concept?
Still working on it?
Don't mean to rush you or anything
No
What do you mean reverse it?
omg I'm so sorry my connection screwed up and I didn't see your reply
Reverse the equation, like A -> B to B -> A. When you do that you reverse the sign of \(\Delta H\)
What is it supposed to look like once you reverse it though? I don't get it
Also, I'm still confused over what the answer would be. Is it B?
Sorry, this is too much to type out, and i have to step out. I think choice 4 is correct. I can help you solve it later if you want to, just tag me.
Thanks.
SO i double checked it and it's A. sorry about that, i can type up a solution if you're still confused.
Join our real-time social learning platform and learn together with your friends!