who would like to help me :)
@SolomonZelman this one
This all is one question, right ?
the attachment and the text.. correct?
I see
So we see point D, and it's x and y coordinates are changes, by multiplying their signs times -1. In other words x1 and x2 and y1 and y2 are both additive inverses of each other
yes
In this case, since you have the coordinate in the 1st quadrant, reflecting over y=x would be good, or applying the rule (x, y) → ( x × {-1} , y × {-1} )
the last attachment you posted doesn't work for me.
Oh now it worked, both attachments are same :)
yeah
isn't that should be choice 2
The only correct transformation you have, to obtain the original points is to reflect across y=x.
ohh ok
thank you sooooooooooo much
Yw, Have fun !
is this one right answer ??
it doesn't work when I click ?
Ohh it worked... yes !
Sometimes attachments work late for me.
when i put this answer they mark me wrong so this is not right answer
it's soo confusing
` changed the signs of the x- and y-coordinates.` And looking at the coordinate D, that is in the 1st quadrant it should be correct. I'll check again though.
Sorry
It is over y=-x
Sorry
I confused it, it is y=-x, because it si going from top left to bottom right, and that's how a point on a top right (first quadrant) should be reflected to reverse the signs.
no problem thanks for explain this problem :)
Anytime !
hm....................
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