Question

8^(y - 2) = 2^y
a.y = 1
b.y = 3
c.y = -3
d.y = -1

Answer 1

Can you convert \( 8^{y-2}\) to a power of 2? That is \( \large2^?\) ?

Answer 2

im lost on what to do

Answer 3

Okay. Let me make it bigger

\[ \Large8^{y-2} \]

is on the left.

\[ \Large 2^y \]

is on the right.

You can solve this problem if you can express both terms as the same base number to some power.

So how can you convert

\[ \Large8^{y-2} \] to

\[ \Large2^{something} \]

Answer 4

do you divide it by 4?

Answer 5

Here's a hint

\[ \Large 8 = 2^3 \]

Answer 6

so the answer would be 3?

Answer 7

\[\Large8^{y-2} \]

is what you are trying to convert.

I just told you

\[\Large 8 = 2^3\]

So what can you do?