Question

question is closed .so stop answering :)

Answer 1

Hints:

\[ \Large {1 \over \sqrt 8 } = 2^{-{3 \over 2}}, 4= 2^2\]

Answer 2

wow that really helps

Answer 3

@iPwnBunnies help please

Answer 4

I'm suggesting you put both sides into expressions with the same base number.

Try making the substitutions I hinted at.

Answer 5

Here is one of the laws of exponents:

\[\Large (x^n)^m = x^{mn} \]

Answer 6

okay

Answer 7

So if you made the substituions, you now have a term which is 2 to some power equal to 2 to some power. Now you can say you are taking the log base 2 of both sides or you can just say if the terms are equal and the have the same base (2), then the exponents must be equal.

Answer 8

read the question

Answer 9

So. This is a learning site. If you just want someone to do your homework, try Yahoo Answers.

Answer 10

:) i don't know if you can read or not but the question now says to stop answering :)