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Geometry 22 Online
OpenStudy (anonymous):

hey guys can you please help me with this, i have no clue Find the area of the image below: http://learn.flvs.net/webdav/assessment_images/educator_geometry/v15/module06/0604_g5_q1.jpg 59 square units 65 square units 72 square units 83 square units

OpenStudy (imstuck):

Bad link.

OpenStudy (anonymous):

@robtobey @RyGuy @HelloJonathan

OpenStudy (imstuck):

Post it a different way.

OpenStudy (anonymous):

how do i do it @IMStuck

OpenStudy (imstuck):

I can't open your link.

OpenStudy (anonymous):

how do i, post pic so you can see it?

OpenStudy (imstuck):

can you draw it?

OpenStudy (anonymous):

OpenStudy (anonymous):

can you see it? @IMStuck

OpenStudy (imstuck):

Yes that's perfect. You need to find the area of that?

OpenStudy (anonymous):

yes

OpenStudy (imstuck):

Ok, let me look at it to see the best way to go about it.

OpenStudy (imstuck):

Ok, the way I would do it the way you will first learn how to figure the area under a curve in calculus...by counting the squares. Literally count the whole squares, then start putting halves together to make one, and you will get your answer. When I counted them I was off by just 1.

OpenStudy (imstuck):

That's the easiest way. The other way is to separate the whole thing into individual shapes, like triangles and squares etc. and then find the individual areas of each and add them together to find the total area. Whichever you want; they will both work here.

OpenStudy (anonymous):

i got 67 lol @IMStuck

OpenStudy (imstuck):

I had gotten 66, but the closest to that is 65. That would be your answer. Do you want me to check it by finding all the individual areas? I can.

OpenStudy (imstuck):

It comes to a perfect 65 when you find all the individual areas. So you were close enough to use your answer to find the correct one. That is how your teacher will probably begin teaching you to find area under a curve before going to Reimann sums.

OpenStudy (anonymous):

oh thank you so much, you are great.. can you maybe help me with one more? @IMStuck

OpenStudy (imstuck):

What do you have?

OpenStudy (anonymous):

Using the image below, find the y value for the point that divides the line segment XY into a ratio of 1:2.

OpenStudy (anonymous):

OpenStudy (anonymous):

−0.7 −2.3 −0.3 −0.2

OpenStudy (anonymous):

@IMStuck

OpenStudy (imstuck):

let me look at it for a sec...

OpenStudy (anonymous):

sure

OpenStudy (imstuck):

Ok this is kind of confusing so I will try to explain it the easiest way I know how. Ok? You are wanting to divide the line so you have 1 segment to 2 segments, which means you are dividing it into 3 equal parts. You want the y coordinate that is one-third the way from x to y. I recommend doing it like this...

OpenStudy (imstuck):

|dw:1407385166835:dw|

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