Ask your own question, for FREE!
Mathematics 26 Online
OpenStudy (anonymous):

Solve 4^x = 12

OpenStudy (imstuck):

Take the log of both sides, like this:

OpenStudy (imstuck):

\[\log4^{x}=\log12\]cuz then you can do this:

OpenStudy (imstuck):

\[x \log4=\log12\]and\[x=\frac{ \log12 }{ \log4 }\]

OpenStudy (solomonzelman):

@makaylarrrrrr have you learned about logarithms though? or do you just need to approximate the exponent?

OpenStudy (solomonzelman):

(I personally agree with IMStuck)

OpenStudy (imstuck):

x = 1.79 if you do logs.

OpenStudy (solomonzelman):

or precisely, \(\normalsize\color{blue}{ \log_412}\).

OpenStudy (anonymous):

\[b^x=A\iff x=\frac{\log(A)}{\log(b)}\] sometimes known as the 'change of base' formula

OpenStudy (anonymous):

thank yall so much!

OpenStudy (anonymous):

\[5^x=7\iff x=\frac{\log(7)}{\log(5)}\] \[4^x=12\iff x=\frac{\log(12)}{\log(7)}\] you should be able to do this quickly of course you need a calculator to get the decimal

OpenStudy (anonymous):

lol cept i made a typo \[4^x=12\iff x=\frac{\log(12)}{\log(4)}\]

OpenStudy (solomonzelman):

Just wanted to simplify, and got disconnected, \(\LARGE\color{blue}{ \frac{\log(12)}{\log(4)} = \frac{\log(4)+\log(3)}{\log(4)}=1+\log_43 }\)

OpenStudy (solomonzelman):

I finished...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!