@makaylarrrrrr have you learned about logarithms though? or do you just need to approximate the exponent?
OpenStudy (solomonzelman):
(I personally agree with IMStuck)
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OpenStudy (imstuck):
x = 1.79 if you do logs.
OpenStudy (solomonzelman):
or precisely, \(\normalsize\color{blue}{ \log_412}\).
OpenStudy (anonymous):
\[b^x=A\iff x=\frac{\log(A)}{\log(b)}\] sometimes known as the 'change of base' formula
OpenStudy (anonymous):
thank yall so much!
OpenStudy (anonymous):
\[5^x=7\iff x=\frac{\log(7)}{\log(5)}\]
\[4^x=12\iff x=\frac{\log(12)}{\log(7)}\] you should be able to do this quickly
of course you need a calculator to get the decimal
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OpenStudy (anonymous):
lol cept i made a typo
\[4^x=12\iff x=\frac{\log(12)}{\log(4)}\]
OpenStudy (solomonzelman):
Just wanted to simplify, and got disconnected,
\(\LARGE\color{blue}{ \frac{\log(12)}{\log(4)} = \frac{\log(4)+\log(3)}{\log(4)}=1+\log_43 }\)