Solve 4^x = 12
Take the log of both sides, like this:
\[\log4^{x}=\log12\]cuz then you can do this:
\[x \log4=\log12\]and\[x=\frac{ \log12 }{ \log4 }\]
@makaylarrrrrr have you learned about logarithms though? or do you just need to approximate the exponent?
(I personally agree with IMStuck)
x = 1.79 if you do logs.
or precisely, \(\normalsize\color{blue}{ \log_412}\).
\[b^x=A\iff x=\frac{\log(A)}{\log(b)}\] sometimes known as the 'change of base' formula
thank yall so much!
\[5^x=7\iff x=\frac{\log(7)}{\log(5)}\] \[4^x=12\iff x=\frac{\log(12)}{\log(7)}\] you should be able to do this quickly of course you need a calculator to get the decimal
lol cept i made a typo \[4^x=12\iff x=\frac{\log(12)}{\log(4)}\]
Just wanted to simplify, and got disconnected, \(\LARGE\color{blue}{ \frac{\log(12)}{\log(4)} = \frac{\log(4)+\log(3)}{\log(4)}=1+\log_43 }\)
I finished...
Join our real-time social learning platform and learn together with your friends!