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OpenStudy (precal):
Determine the point on the line y=2x+3 so that the distance between the line and the point (1,2) is a minimum.
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OpenStudy (precal):
@ganeshie8
ganeshie8 (ganeshie8):
geometrically, we can find the point easily by solving system of equations :
1) y=2x+3
2) y = -1/2x + 5/2
we want to work it usign calculus, right ?
OpenStudy (precal):
yes but how did you get that second equation?
ganeshie8 (ganeshie8):
|dw:1407413850936:dw|
OpenStudy (ikram002p):
geometricly ,the minimum distance is the perpendiculer one
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ganeshie8 (ganeshie8):
shortest distance between point and a line = `perpendicular` distance from the point to the line
ganeshie8 (ganeshie8):
lets work ut using calculus by optimizing the `distance` expression
OpenStudy (precal):
oh ok
ganeshie8 (ganeshie8):
any point on the given line = (x, y) = (x, 2x+3)
given point : (1, 2)
ganeshie8 (ganeshie8):
optimizing distance(d) is same as optimizing its square(d^2) :
\[\large (x-1)^2 + (2x+1)^2\]
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ganeshie8 (ganeshie8):
optimize ^^
OpenStudy (precal):
where did 2x+1 come from?
ganeshie8 (ganeshie8):
apply distance formula for the points :
(x, 2x+3)
(1, 2)
|dw:1407414242255:dw|
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