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Mathematics 14 Online
OpenStudy (precal):

Determine the point on the line y=2x+3 so that the distance between the line and the point (1,2) is a minimum.

OpenStudy (precal):

@ganeshie8

ganeshie8 (ganeshie8):

geometrically, we can find the point easily by solving system of equations : 1) y=2x+3 2) y = -1/2x + 5/2 we want to work it usign calculus, right ?

OpenStudy (precal):

yes but how did you get that second equation?

ganeshie8 (ganeshie8):

|dw:1407413850936:dw|

OpenStudy (ikram002p):

geometricly ,the minimum distance is the perpendiculer one

ganeshie8 (ganeshie8):

shortest distance between point and a line = `perpendicular` distance from the point to the line

ganeshie8 (ganeshie8):

lets work ut using calculus by optimizing the `distance` expression

OpenStudy (precal):

oh ok

ganeshie8 (ganeshie8):

any point on the given line = (x, y) = (x, 2x+3) given point : (1, 2)

ganeshie8 (ganeshie8):

optimizing distance(d) is same as optimizing its square(d^2) : \[\large (x-1)^2 + (2x+1)^2\]

ganeshie8 (ganeshie8):

optimize ^^

OpenStudy (precal):

where did 2x+1 come from?

ganeshie8 (ganeshie8):

apply distance formula for the points : (x, 2x+3) (1, 2) |dw:1407414242255:dw|

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