Question

help!!!needed
2.24 L methane gas is mixed with 1.12 L of ethane gas in cylinder with movable piston at SATP where pressure is 1 atm and temperature is 298 k.The total number of carbon atoms present in this mixture at SATP is?

Answer 1

@hartnn @ganeshie8

Answer 2

pv =nRT this equation may help to solve this problem

Answer 3

I tried..can you elaborate it....

Answer 4

what did you do so far?

Answer 5

I didn't understand the question.... @aaronq

Answer 6

you said you tried using the ideal gas law.

What you wanna do is find the moles of each gas separately using PV=nRT

Then use the moles to find the number of carbon atoms

Answer 7

explanation please...!! @aaronq

Answer 8

have you tried doing it yourself?

Answer 9

yes ....

Answer 10

@chmvijay

Answer 11

can u show me what you did ?

Answer 12

Step 1
Use PV=nRT formula to find mole of EACH methane gas and ethane gass

Answer 13

n=PV/RT
P= 1 atm
V1= 2.24 for methane
V2= 1.12 for ethane
R= constant value 0.08206
T= 298K

so now solve this using V1 meaning methane value and get the mole
then solve it again but now using V2 meaning ethane value and get ethane mole

Answer 14

Step 2
after getting mole of both

now our target is mole of C in methane and ethane

so knowing mole of methane we can do this mathematically like this :

mole of methane = molecular mass of methane
Unknown mole of Carbon = molecular mass of Carbon

Molecular mass i'll write as Mr
\[Unknown~mole~of~C =\frac{ mole ~of~Methane \times Mr~of ~ C }{ Mr~of~Methane }\]

and so you get mole of C in Methane

do same thing but now using mole of Ethane and get the answer

Answer 15

Step 3
now you have mole of C in methane and in ethane
so add both moles up and get total mole
and then
\[No.~of~C~atoms= total~mole~of~C \times (6.02 \times 10^{23}) \]

Answer 16

6.02 * 10 ^23 is Avogadro constant btw

Answer 17

is it clear i hope?

Answer 18

thanks @Somy

Answer 19

no problem :)