Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Write an indirect proof to show that opposite sides of a parallelogram are congruent. Be sure to create and name the appropriate geometric figures. This figure does not need to be submitted.

OpenStudy (anonymous):

If you cut off part of a parallelogram, and move it to the other end, the parallelogram becomes a square. That's all you need.

OpenStudy (anonymous):

That's my entire answer?

OpenStudy (imnotgoodatmath):

the answer will be Consider two triangles ABC and CDA as the figure we had. In triangles, 1. <CBA = <ACD (the line AC is a transversal of parallel lines AB and CD,hence Angle CAB and ACD are alternate angles) 2. <ACB=<CAD (The line AC is a transversal of parallel lines BC and DA,hence Angle ACB and Angle CAD are alternate angles) 3. AC=CA (The common side to two triangles) From conditions 1,2 and 3, Triangles ABC and CDA are congruent (By Angle -Side-Angle congruency property) Hence as triangles are congruent triangles , the corresponding sides are equal,

OpenStudy (imnotgoodatmath):

Hence, AB = CD and BC = DA.

OpenStudy (imnotgoodatmath):

Consider this parallelogram

OpenStudy (anonymous):

It's not your entire answer, you can build on that principle.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!