Write an indirect proof to show that opposite sides of a parallelogram are congruent. Be sure to create and name the appropriate geometric figures. This figure does not need to be submitted.
If you cut off part of a parallelogram, and move it to the other end, the parallelogram becomes a square. That's all you need.
That's my entire answer?
the answer will be Consider two triangles ABC and CDA as the figure we had. In triangles, 1. <CBA = <ACD (the line AC is a transversal of parallel lines AB and CD,hence Angle CAB and ACD are alternate angles) 2. <ACB=<CAD (The line AC is a transversal of parallel lines BC and DA,hence Angle ACB and Angle CAD are alternate angles) 3. AC=CA (The common side to two triangles) From conditions 1,2 and 3, Triangles ABC and CDA are congruent (By Angle -Side-Angle congruency property) Hence as triangles are congruent triangles , the corresponding sides are equal,
Hence, AB = CD and BC = DA.
http://assets.openstudy.com/updates/attachments/52e74667e4b096fa405b41e8-yttrium-1390888812280-1.jpg
Consider this parallelogram
It's not your entire answer, you can build on that principle.
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