Question

MEDAL HELLP PLEASE
What Is The Center and Radius of a circle (x-5)^2 /16 + (y-2)^2/16 = 1

Answer 1

@bigballlz

Answer 2

@sidsiddhartha

Answer 3

this is of the form\[(x-a)^2+(y-b)^2=c^2\]
for this circle
center=(a,b)
radius=c

Answer 4

I know the radius is 4 but i have no clue what the center is

Answer 5

\[\frac{ (x-5)^2 }{ 16 }+\frac{ (y-2)^2 }{ 16 }=1\]so it can be written as
\[(x-5)^2+(y-2)^2=16\]
now just comparing it with the above equation
so center is=(5,2) and
\[c^2=16\rightarrow c=4\]
radius is 4

Answer 6

THANKS Boo