a resistor r and another resistor 2R are connected in parallel across a battery if heat is produced at a rate of 10 w in r then in 2R its produced at a rate of
40 W
20 W
10 W
5 W
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OpenStudy (anonymous):
@rock_mit182
@robtobey
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@hartnn
OpenStudy (fifciol):
\[P=\frac{ V^2 }{R }\]
determine the voltage, then use this expression to calculate the power dissipated by resistance 2R. Because they're connected in parallel they have the same voltage across their terminals
OpenStudy (anonymous):
why is it V^2
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OpenStudy (anonymous):
i thought P = IV
OpenStudy (anonymous):
yea I got it now
OpenStudy (fifciol):
element law for resistor :\[V=IR \Rightarrow I=\frac{ V }{ R }\]
OpenStudy (anonymous):
ok so since we have same voltage then if R is doubled then the P will be half
so the answer is 5 W?
OpenStudy (fifciol):
yes, that's correct answer
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