Ask your own question, for FREE!
Physics 20 Online
OpenStudy (anonymous):

a resistor r and another resistor 2R are connected in parallel across a battery if heat is produced at a rate of 10 w in r then in 2R its produced at a rate of 40 W 20 W 10 W 5 W

OpenStudy (anonymous):

@rock_mit182 @robtobey

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@hartnn

OpenStudy (fifciol):

\[P=\frac{ V^2 }{R }\] determine the voltage, then use this expression to calculate the power dissipated by resistance 2R. Because they're connected in parallel they have the same voltage across their terminals

OpenStudy (anonymous):

why is it V^2

OpenStudy (anonymous):

i thought P = IV

OpenStudy (anonymous):

yea I got it now

OpenStudy (fifciol):

element law for resistor :\[V=IR \Rightarrow I=\frac{ V }{ R }\]

OpenStudy (anonymous):

ok so since we have same voltage then if R is doubled then the P will be half so the answer is 5 W?

OpenStudy (fifciol):

yes, that's correct answer

OpenStudy (anonymous):

ok thnx man I have some more can you help me out

OpenStudy (fifciol):

yes, you can post them

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!